4x^2-72x-144=0

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Solution for 4x^2-72x-144=0 equation:



4x^2-72x-144=0
a = 4; b = -72; c = -144;
Δ = b2-4ac
Δ = -722-4·4·(-144)
Δ = 7488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7488}=\sqrt{576*13}=\sqrt{576}*\sqrt{13}=24\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-24\sqrt{13}}{2*4}=\frac{72-24\sqrt{13}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+24\sqrt{13}}{2*4}=\frac{72+24\sqrt{13}}{8} $

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